# Line slope calculator x+6y=8

**Straight line given by points A[2; 1] and B[8; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.1667x+1.3333

**Canonical form of the line equation:**x+6y-8 = 0

**Parametric form of the line equation:**

x = 6t+2

y = -t+1 ; t ∈ R

**Slope:**m = -0.1667

**Slope angle of line: φ =**-9°27'44″ = -0.1651 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = 1.3333

**Distance line from the origin:**d

_{0}= 1.3152

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(6; -1)

**Normal vector: n =**(1; 6)

**Midpoint of the segment AB: M =**[5; 0.5]

**Perpendicular Bisector equation:**6x-y-29.5 = 0

**Vector OA = (2; 1) ; |OA| = 2.2361**

**Vector OB = (8; 0) ; |OB| = 8**

**Scalar product OA .OB = 16**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**